2^(9-3x)=1/64

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Solution for 2^(9-3x)=1/64 equation: 



2^(9-3x)=1/64

We move all terms to the left:

2^(9-3x)-(1/64)=0

We add all the numbers together, and all the variables

2^(-3x+9)-(+1/64)=0

We get rid of parentheses

2^(-3x+9)-1/64=0

We multiply all the terms by the denominator


(2^(-3x+9))*64-1=0

We move all terms containing x to the left, all other terms to the right

(2^(-3x+9))*64=1

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